Celebrate Earth Day With This Organic LSAT Logic Game
- Apr 24, 2015
- LSAT, Sample Logic Games
- Reviewed by: Matt Riley
Happy belated Earth Day! The Earth might be doomed, but you can still save your LSAT score.
We may be a day late and a dollar short, but in honor of the Earth Day yesterday, MSS is happy to bring you an organic, locally sourced, and reusable LSAT Logic Game! Give it a try, and think of it as penance for your high carbon lifestyle.
Three recycling centers, A, B, and C, will each recycle at least one type of material: P, Q, R, and S. The assignment of materials to centers will adhere to the following rules:
Each material will be recycled by at least one recycling center.
B recycles any material recycled by A.
Material Q is recycled by at most one recycling center.
P is recycled at a center if but only if R is recycled at the same center.
B and C cannot recycle the same materials.
C recycles S.
1. How many of the materials must be recycled at exactly one center?
2. Which one of the following is a complete and accurate list of the materials that can be recycled at all three centers?
(B) P, R
(C) P, S
(D) P, R, S
(E) P, R, Q
3. Which one of the following could be true?
(A) P is recycled at center C, and R is recycled at center B.
(B) C is the only center that recycles P.
(C) B is the only center that recycles Q.
(D) S and R are recycled at the same center.
(E) C recycles all four materials.
4. If A recycles R, and S is not recycled at the same center as P, then which one of the following must be true?
(A) C recycles exactly one type of material.
(B) S is recycled at more centers than Q.
(C) Q and S are recycled at the same center.
(D) B recycles more materials than A.
(E) A recycles exactly two types of materials.
5. Which one of the following must be false?
(A) A recycles exactly two types of materials.
(B) B recycles Q.
(C) C recycles R.
(D) C recycles Q.
(E) P is recycled at two recycling centers.
6. Which one of the following could be a complete and accurate assignment of materials to centers?
(A) A: P; B: P, R; C: Q, S
(B) A: S; B: P, R; C: Q, S
(C) A: P, R; B: P, R; C: S
(D) A: P, R, Q; B: P, R; C: S
(E) A: P, R; B: P, R, Q; C: S
1. There’s a principle of distribution hidden in the intro.
2. Represent rule 2 correctly. “Any” is a sufficient condition indicator.
3. Combine rules 1 and 3. Then combine the result with rule 2.
4. Combine rules 5 and 6. Then combine the result with the contrapositive of rule 2.
5. Create scenarios based on rule 4.
(Answer Key: 1: C; 2: A; 3: C; 4: E; 5: C; 6: E)
A version of this post was originally published on 4/22/14.
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