PCAT Biological Processes – Genotypes
 by
 Feb 19, 2018
 PCAT Question of the Day
What proportion of offspring with the genotype AABBCC will result from a trihybrid cross for the unlinked genes A, B, and C?
 1/8
 1/16
 1/32
 1/64
Click for Explanation
This question tests your ability to calculate the probability of a possible genotype resulting from a trihybrid cross between two heterozygotes. One method to determine the probability is to make a Punnett square. An organism that is heterozygous for three genes can produce eight different gamete possibilities. Thus, resultant Punnett square would contain an 8×8 table with a total of 64 genotype combinations. A more efficient method is to calculate the probability of each event occurring separately and then use the rule of multiplication to determine the likelihood of all three events occurring at the same time.
Probability of obtaining an AA genotype from a cross between Aa and Aa = ¼
Probability of obtaining a BB genotype from a cross between Bb and Bb = ¼
Probability of obtaining a CC genotype from a cross between Cc and Cc = ¼
Total probability of all three possibilities = ¼ x ¼ x ¼ = 1/64
Search the Blog
Free Consultation
Interested in our Online MCAT Course or one of our OneonOne MCAT Tutoring packages? Set up a free consultation with one of our experienced Academic Managers!
Schedule NowPopular Posts

MCAT Blog How to Review MCAT FullLengths
Free MCAT Practice Account
Need great MCAT practice?Get the most representative MCAT practice possible when you sign up for our free MCAT Account, which includes a halflength diagnostic exam and one of our fulllength MCAT practice exams.
Learn More
Submit a Comment