MCAT Physics Question — Sound Level
- Apr 03, 2017
- MCAT Question of the Day
Click for Explanation
dB = 10log10(I/Io)
120 = 10log10(I120/Io)
12 = log10(I120/Io)
I120 = Io1012
dB = 10log10(I40/Io)
40 = 10log10(I40/Io)
4 = log10(I40/Io)
I40 = Io104
I120/I40 = Io1012/Io104
I120/I40 = 108
Thus, the intensity of the sound at 120 decibels is eight orders of magnitude greater than sound at 40 decibels making B the correct answer.
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