What is the identity of the reducing agent and oxidizing agent, respectively, in the reaction shown below?
2Cr(OH)3 + 3H2O2 + 4NaOH → 2Na2CrO4 + 8H2O
- Cr(OH)3 and NaOH
- Cr(OH)3 and H2O2
- H2O2 and Cr(OH)3
- H2O2 and NaOH
Click for Explanation
To answer this question, you must identify the atom that is reduced and the atom that is oxidized. In the reaction above, chromium is oxidized from +3 to +6, which makes chromium hydroxide the reducing agent. Alternatively, oxygen in hydrogen peroxide is reduced from -1 to -2, which makes it the oxidizing agent. Thus, the correct answer is B.
Want more MCAT practice?
We’ve got options for every schedule and learning style!
Whether you need the flexibility of a Self-Paced Course, the instruction of a live 515+ Course, or the 1:1 attention of a private MCAT tutor, Blueprint MCAT has the MCAT prep option that works for your learning style!
Get started with a free MCAT diagnostic, one free practice exam, and tons more MCAT prep resources.
Not sure which option is right for you? Schedule a free MCAT consultation with an MCAT expert using the form below. No obligation, just expert advice.
