Fluoride is a very weak base that is added to drinking water at a concentration of 0.7 mg/L. This concentration strengthens the enamel of the tooth surface to prevent the formation of cavities. The pKb of this base would likely be:
A. equal to the pOH of the solution.
B. higher than the pOH of the solution.
C. lower than the pOH of the solution.
D. near 7 at 25ºC.
Click for Explanation
B + H2O <—-> HB+ + OH–
Kb = [OH–][HB+]/[B]
Using an alternate form of the Henderson-Hasselbalch equation, expressed in terms of pOH and pKb:
where [HB+] and [B] represent the concentrations of the conjugate acid and original base molecule at equilibrium, respectively. A very weak base will have a very small Kb. This means that equilibrium favors the reactants (including [B]) over the products (including [HB+]). Thus, we can infer that the value of [HB+]/[B] << 1, making the value of log [HB+]/[[B] << 0. This would result in a pOH value that is less than the pKb. Thus, pKb > pOH.
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