The fundamental wavelength of a standing wave in a 1 meter long pipe, if the pipe has one open end and one closed end is:
A. 4m
B. 1m
C. 2m
D. 4/3m
Click for Explanation
Standing waves consist of wave frequencies at which wave nodes occur at closed pipe ends and antinodes occur at open pipe ends.
For a pipe closed at one end, the equation relating the length of the pipe, L, to the λ of a standing wave in the pipe is λ = 4L / n, where n is the harmonic number, and can be any odd integer.
When n = 1, the standing wave is the “fundamental” wavelength. This is also called the “first harmonic”.
A. 4m, correct, the fundamental wavelength for a pipe with one closed end is λ1= 4L.
B. 1m, incorrect , the pipe length does not correspond to the fundamental wavelength.
C. 2m, incorrect, 2m corresponds to the fundamental wavelength of a pipe with both ends open λ1= 2L.
D. 4/3m, incorrect, 4/3m corresponds to the second resonant wavelength of a pipe with one end open, λ2= 4L/3.
Want more MCAT practice?
We’ve got options for every schedule and learning style!
From the best online MCAT course created by top instructors with 524+ MCAT scores to the most representative full-length practice exams and private tutoring, we can custom tailor your MCAT prep to your goals!
Not sure which option is right for you? Schedule a free MCAT consultation with an MCAT expert using the form below. No obligation, just expert advice.
Related Posts
Search the Blog
Free Consultation
Interested in our Online MCAT Course, One-on-One MCAT Tutoring or Med admissions packages? Set up a free consultation with one of our experienced Senior Student Advisors.
Schedule NowPopular Posts
-
-
MCAT Blog What's on the MCAT? -
-
-
MCAT Blog How to Review MCAT Full Lengths
Free MCAT Practice Account
Need great MCAT practice?Get the most representative MCAT practice possible when you sign up for our free MCAT Account, which includes a half-length diagnostic exam and one of our full-length MCAT practice exams.
Learn More