The electric field a distance rA from a positively charged point charge is equal to EA. What is the ratio EB to EA of the electric field at point B a distance of 3rA from the charge?
A. EB = 1/9 EA
B. EB = 1/3 EA
C. EB = 3EA
D. EB = 9EA
Click for Explanation
This question asks the examinee to determine the ratio of the electric field due to a point charge as a function of distance. The electric field of a point charge is given by the following equation:
E = kq/r2
Therefore, the ratio of the electric field at point B to point A is equal to:
EB / EA = (kq/rB2) / (kq/rA2) = rA2 / rB2 = rA2 / 9rA2 = 1/9
Thus, EB = 1/ 9 EA making A the correct answer.
Want more MCAT practice?
We’ve got options for every schedule and learning style!
From the best online MCAT course created by top instructors with 524+ MCAT scores to the most representative full-length practice exams and private tutoring, we can custom tailor your MCAT prep to your goals!
Not sure which option is right for you? Schedule a free MCAT consultation with an MCAT expert using the form below. No obligation, just expert advice.
