MCAT Physics Question — Electric Field
- by
- Jun 10, 2017
- MCAT Question of the Day
A. EB = 1/9 EA
B. EB = 1/3 EA
C. EB = 3EA
D. EB = 9EA
Click for Explanation
E = kq/r2
Therefore, the ratio of the electric field at point B to point A is equal to:
EB / EA = (kq/rB2) / (kq/rA2) = rA2 / rB2 = rA2 / 9rA2 = 1/9
Thus, EB = 1/ 9 EA making A the correct answer.
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