Attachment data exported to attachments.csv. MCAT Chemistry — Spontaneous Reaction, Oxidation
Return to MCAT® Blog Homepage

MCAT Chemistry Question — Spontaneous Reaction

What species is oxidized and what is the oxidizing agent in the following spontaneous reaction?

2Au3+(aq) + 3Cu (s) 2Au (s) +3Cu2+ (aq)

A) Au3+, Au

B) Cu, Cu2+

C) Au3+, Cu

D) Cu, Au3+

Explanation

For the MCAT, remember: oxidation is loss of electrons (OIL) and reduction is gain of electrons (RIG). The compound containing the element that is reduced is the oxidizing agent, and the compound containing the element that is oxidized is the reducing agent.

In this reaction, Cu (s) is oxidized because it loses 2 e. Au3+ is the oxidizing agent because, although monatomic, it is the element in the compound that is reduced.

A) Au3+(aq), Au (s), incorrect, Au3+ (aq) is reduced to Au (s), and Au (s) is a product.

B) Cu (s), Cu2+ (aq), incorrect, Cu(s) is oxidized, and therefore the compound containing Cu (s) is the reducing agent. Note that although Cu (s) is the reducing agent in this reaction, the entire compound would be the reducing agent if the Cu were in a polyatomic molecule.

C) Au3+ (aq), Cu (s), incorrect, Au3+ (aq) is reduced, and Cu (s) is oxidized.

D) Cu (s), Au3+ (aq), correct.

Want more MCAT practice?

We’ve got options for every schedule and learning style!

From the best online MCAT course created by top instructors with 524+ MCAT scores to the most representative full-length practice exams and private tutoring, we can custom tailor your MCAT prep to your goals!

Not sure which option is right for you? Schedule a free MCAT consultation with an MCAT expert using the form below. No obligation, just expert advice.

Create your Free Account to access our MCAT Flashcards SIGN UP NOW
MCAT is a registered trademark of the Association of American Medical Colleges (AAMC), which is not affiliated with Blueprint.