MCAT Chemistry Question — Solubility Product
 by
 Jul 10, 2017
 MCAT Question of the Day
A. 4 x 10^{10}
B. 4.8 x 10^{19}
C. 6.9 x 10^{37}
D. cannot be determined without knowing the [OH^{–}] concentration
Click for Explanation
Therefore, the solubility product K_{sp }= [Fe^{3+}]^{1}[OH^{–}]^{3 }= [Fe^{3+}]^{1}{3[Fe^{3+}]}^{3}
The math works out to (4 x 10^{10}) x (27 x 64 x 10^{30}), and only the correct choice c) is close enough.
A. 4 x 10^{10}, incorrect, This answer disregards the [OH^{–}] concentration.
B. 4.8 x 10^{19}, incorrect, This answer disregards the power of 3 on the [OH^{–}] ion.
C. 6.9 x 10^{37}, correct.
D. cannot be determined without knowing the [OH^{–}] concentration, incorrect, The [OH^{–}] concentration is known by the multiplying the given [Fe^{3+}] concentration by 3.
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