Return to MCAT® Blog
Homepage
MCAT Chemistry Question — Faraday
- by
- Jul 01, 2014
- Chemistry, MCAT Blog, MCAT Chemistry
- Reviewed By: Liz Flagge
When 1 mole of Cu2+(aq) is reduced to Cu (s), how many faraday of charge are required?
A) 1
B) 2
C) 6.02 x 1023
D) none, charge is measured in Coulombs (C)
Explanation
Faraday is a measure of 1 mole of electric charge equal to approximately 1 x 105 coulomb. In this question, 2 moles of electrons are required for the reduction, b) is correct.
A) 1, incorrect, 2 moles of charge are required.
B) 2, correct.
C) 6.02 x 1023, incorrect, Although this is the number of electrons in a mole of electrons, the faraday is a measure of 1 mole of charge.
D) none, charge is measured in Coulombs (C), incorrect, Although charge is measured in coulomb’s, it is also (less commonly) measured in faraday. Either unit may appear on the MCAT.
Related Posts
Search the Blog
Free Consultation
Interested in our Online MCAT Course, One-on-One MCAT Tutoring or Med admissions packages? Set up a free consultation with one of our experienced Senior Student Advisors.
Schedule NowPopular Posts
-
-
MCAT Blog What's on the MCAT? -
-
-
MCAT Blog How to Review MCAT Full Lengths
Free MCAT Practice Account
Need great MCAT practice?Get the most representative MCAT practice possible when you sign up for our free MCAT Account, which includes a half-length diagnostic exam and one of our full-length MCAT practice exams.
Learn More