What is the ratio of the ratio of the absolute pressure at point A compared to point B if the open container shown below is filled with water?
A. Pb = 2Pa
B. Pb = 3Pa
C. Pb = 4Pa
D. Pb = 5Pa
Click for Explanation
This question is asking you to determine the ratio of the absolute pressure of Point B to Point A. To answer this question, you must determine the absolute pressure at each point. The absolute pressure is equal to the atmospheric pressure plus the gauge pressure, as shown in the equation, Pabs = Patm + Pgauge.
The atmospheric pressure exerted on the surface of the fluid is equal to 101,000 N/m2 (1 atm). To calculate the gauge pressure at each point, you must apply the formula, Pgauge = ρgh, where Pgauge is the pressure due to the water column of height h, ρ is the density of the fluid, g is the gravitational acceleration constant, and h is the depth.
Pabs (A) = Patm + Pgauge (A)
Pabs (A) = (101,000 N/m2)+ ρwaterghA
Pabs (A) = (101,000 N/m2) + (1000 kg/m3)(10 m/s2)(10 m)
Pabs (A) = 201,000 N/m2
Pabs (B) = Patm + Pgauge (B)
Pabs (B) = (101,000 N/m2)+ ρwaterghB
Pabs (B) = (101,000 N/m2) + (1000 kg/m3)(10 m/s2)(30 m)
Pabs (B) = 401,000 N/m2
Therefore, the PB = 2PA making answer choice A the correct answer. Furthermore, an increase in depth of 10 m in water equals 1 atmosphere. Therefore, the total pressure at A is 2 atm while the total pressure at B is 4 atm.
Want more MCAT practice?
We’ve got options for every schedule and learning style!
Whether you need the flexibility of a Self-Paced Course, the instruction of a live 515+ Course, or the 1:1 attention of a private MCAT tutor, Blueprint MCAT has the MCAT prep option that works for your learning style!
Get started with a free MCAT diagnostic, one free practice exam, and tons more MCAT prep resources.
Not sure which option is right for you? Schedule a free MCAT consultation with an MCAT expert using the form below. No obligation, just expert advice.
