Return to Blog Homepage

PCAT Chemical Processes – Spontaneous Reaction

by Sam
Oct 25, 2017
PCAT Question of the Day

Consider the following reaction:

C₆H₁₂O₆ (s) + 6 O₂ (g) → 6 CO₂ (g) + 6 H₂O (l) ΔH = – 2808 kJ / mol

Under what conditions will this reaction proceed spontaneously?

A. Low temperature, low pressure

B. Low temperature, any pressure

C. High temperature, any pressure

D. Any temperature, any pressure

Explanation

Spontaneity is determined by a negative ΔG value in Gibbs free energy equation:

ΔG = ΔH – TΔS

A reaction with a negative ΔH and a positive ΔS will thus be spontaneous under any conditions. The reaction given has a negative ΔH. It also involves converting 1 mole of solid and 6 moles of gas into 6 moles of liquid and 6 moles of gas. That phase change means entropy is increasing (solid to liquid). Thus, with a negative ΔH and a positive ΔS this reaction is spontaneous under any conditions and (D) is the right answer.

A, B: Reactions with a negative ΔH and a negative ΔS are spontaneous at low temperatures (e.g. the freezing of water from liquid to solid).

C: Reactions with a positive ΔH and a positive ΔS are spontaneous at high temperatures (e.g. the boiling of liquid water into steam)

Submit a Comment

Search the Blog

Free Consultation

Interested in our Online MCAT Course or one of our One-on-One MCAT Tutoring packages? Set up a free consultation with one of our experienced Academic Managers!

Schedule Now

Free MCAT Practice Account

Need great MCAT practice?

Get the most representative MCAT practice possible when you sign up for our free MCAT Account, which includes a half-length diagnostic exam and one of our full-length MCAT practice exams.

Learn More