PCAT Chemical Processes – Reduction & Oxidation
- Oct 25, 2017
- PCAT Question of the Day
What is the identity of the reducing agent and oxidizing agent, respectively, in the reaction shown below?
2Cr(OH)3 + 3H2O2 + 4NaOH → 2Na2CrO4 + 8H2O
- Cr(OH)3 and NaOH
- Cr(OH)3 and H2O2
- H2O2 and Cr(OH)3
- H2O2 and NaOH
To answer this question, you must identify the atom that is reduced and the atom that is oxidized. In the reaction above, chromium is oxidized from +3 to +6, which makes chromium hydroxide the reducing agent. Alternatively, oxygen in hydrogen peroxide is reduced from -1 to -2, which makes it the oxidizing agent. Thus, the correct answer is B.
Search the Blog
Free ConsultationSchedule Now
MCAT Blog How to Review MCAT Full-Lengths
Free MCAT Practice AccountNeed great MCAT practice?
Get the most representative MCAT practice possible when you sign up for our free MCAT Account, which includes a half-length diagnostic exam and one of our full-length MCAT practice exams.Learn More